Correct Answer - Option 1 : 25 days
Given:
3 men + 6 women complete the work in 5 days
The efficiency of man (M) = 3 × Efficiency of a woman (W)
Concept used:
If the work complete in n days
then one day work be 1/n part of total work
Calculation:
Let the total work be 1 unit
Let the one day work of man be M and woman be W
One day work by 3 men and 6 women = 1/5
⇒ 3M + 6W = 1/5 ----(1)
According to the question
1M = 3W
⇒ W = (1/3)M
Substitute in equation (1), we get
⇒ 3M + (6/3)M = 1/5
⇒ 5M = 1/5
⇒ M = 1/25
One day work of man = 1/25
⇒ Number of days = 25
∴ In 25 days the man completes the work alone.