Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.6k views
in Mathematics by (130k points)

A window is in the form of rectangle surmounted by a semicircular opening. The total perimeter of the window is 10 m. Find the dimensions of the window to admit maximum light through the whole opening.

1 Answer

0 votes
by (93.8k points)
selected by
 
Best answer

Let x and y be the length and breadth of the rectangular window.
Radius of the semicircular opening =x/2

It is given that the perimeter of the window is 10 m.

Therefore, by second derivative test, the area is the maximum when length . x= 20/(π+4) m.
Now,

Hence, the required dimensions of the window to admit maximum light is given

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...