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The sum of three consecutive odd numbers is 42 more than the average of these numbers. Which of the following is the smallest among these numbers?
1. 19
2. 13
3. 17
4. 25

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Correct Answer - Option 1 : 19

Let the three consecutive odd numbers are x, x + 2, x + 4 

According to the question,

 x + x + 2 + x + 4 =  [(x + x + 2 + x + 4) ÷ 3] + 42

3x + 6 - 42  = (  3x + 6 ) ÷ 3

3x - 36 =  x + 2

x = 19 

Now, the three consecutive odd numbers are 19, (19 + 2), (19 + 4).

So, the smallest among these numbers is 19.

Hence, Option (1) is correct.

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