Correct Answer - Option 1 : 19

Let the three consecutive odd numbers are x, x + 2, x + 4

According to the question,

x + x + 2 + x + 4 = [(x + x + 2 + x + 4) ÷ 3] + 42

3x + 6 - 42 = ( 3x + 6 ) ÷ 3

3x - 36 = x + 2

x = 19

Now, the three consecutive odd numbers are 19, (19 + 2), (19 + 4).

So, the smallest among these numbers is **19**.

Hence, **Option (1) **is correct.