Correct Answer - Option 1 : 19
Let the three consecutive odd numbers are x, x + 2, x + 4
According to the question,
x + x + 2 + x + 4 = [(x + x + 2 + x + 4) ÷ 3] + 42
3x + 6 - 42 = ( 3x + 6 ) ÷ 3
3x - 36 = x + 2
x = 19
Now, the three consecutive odd numbers are 19, (19 + 2), (19 + 4).
So, the smallest among these numbers is 19.
Hence, Option (1) is correct.