Correct Answer - Option 1 : Monday

The logic that follows here is:

If the given year is the leap year then it has 2 odd days and if the given year is a normal year then it has only 1 odd day.

Here, we have to find the day on 7th March 2004.

Since 2004 is a leap year it has 2 odd days.

But, as we are calculating from March 2005 to March 2004, we are not considering February 2004.

Therefore, from March 2005 to March 2004, there is only one odd day.

So, the day on 6^{th} March 2004 would be 1 day before to the day on 6^{th} March 2005.

We have given that, on 6th March 2005 there was a Monday then,

on 6th March 2004 there would be Sunday.

Now, we have to find the day on 7th March 2004.

If on 6th March 2004 there was a Sunday then on 7th March 2004 there was a Monday.

Hence, the correct answer is** Monday**.