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A is twice as good a workman as B and together, they finish a piece of work in 18 days. In how many days will A alone finish the work?
1. 28 days
2. 30 days
3. 27 days
4. 29 days

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Correct Answer - Option 3 : 27 days

Given:

Efficiency of A = 2 × Efficiency of B

They together can complete the whole work in 18 days

Concept Used:

Work = Efficiency × Time

Calculation:

We have 

Efficiency of A : Efficiency of B = 2 : 1

Efficiency of (A + B) = 3

Total Work = 3 × 18 = 54 units 

A alone can do this work in 54/2 days    [Total work/efficiency of A]

⇒ 27 days.

∴ The time taken by A to complete the work is 27 days.

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