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If the average of 4 consecutive even numbers is 55 then what is the largest number?
1. 50
2. 58
3. 52
4. 54

1 Answer

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Best answer
Correct Answer - Option 2 : 58

Given:

The average of four consecutive numbers = 55

Concept:

\(Average\ =\ {The\ sum\ of\ all\ the\ items \over The\ total\ number\ of\ item}\)

Calculation:

Let us assume the four consecutive even numbers are X, (X + 2), (X + 4), (X + 6),

⇒ \({X\ +\ X\ +\ 2\ +\ X\ +\ 4\ +\ X\ +\ 6\ \over 4}\ =\ 55\)

⇒ 4X + 12 = 220

⇒ 4X = 220 - 12

⇒ X = 208/4 = 52

⇒ The largest number = X + 6 = 52 + 6 = 58

∴ The required result will be 58.

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