Correct Answer - Option 3 : 96 km/h

**Given:**

Amit travelled at 48 km/h from place A to B in a certain time

**Calculation:**

Let be assume distance is D and time is T for the onward journey

⇒ Onward journey time T = D/48 ..... (1)

⇒ Speed of return journey at the beginning S_{1} = (D/3)/(2T/3) = D/2T ..... (1)

⇒ The speed for the remaining return journey S_{2} = (2D/3)/(T/3) = 2D/T ...... (2)

⇒ S_{2} = 2 × (48T)/T = 96 km/h {By equation (2) and (1)}

**∴ The required result will be 96 km/h.**