Correct Answer - Option 3 : 96 km/h
Given:
Amit travelled at 48 km/h from place A to B in a certain time
Calculation:
Let be assume distance is D and time is T for the onward journey
⇒ Onward journey time T = D/48 ..... (1)
⇒ Speed of return journey at the beginning S1 = (D/3)/(2T/3) = D/2T ..... (1)
⇒ The speed for the remaining return journey S2 = (2D/3)/(T/3) = 2D/T ...... (2)
⇒ S2 = 2 × (48T)/T = 96 km/h {By equation (2) and (1)}
∴ The required result will be 96 km/h.