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If T is the capacity of a track in bytes, and S is the capacity of each surface in byte, then (T, S) = _____.
1. (50 K, 50000 K)
2. (25 K, 25000 K)
3. (25 K, 50000 K)
4. (40 K, 36000 K)

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Correct Answer - Option 3 : (25 K, 50000 K)

The correct answer is option 3.

Track capacity = bytes/sector × sectors/track = 512 × 50 = 25K bytes/track 
Surface capacity = bytes/track × tracks/surface = 25K × 2000 = 50, 000K  bytes/surface 

∴ Hence the correct answer is (25 K, 50000 K).

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