Question

Consider the following recursive Java function f that takes two long arguments and returns a float value:

public static float f (long m, long n) {

float result = (float)m / (float)n;

if(m < 0 | n < 0) return 0.of;

else result - = f(m * 2,n * 3);

return result ;

}

Which of the following real values best approximates the value of f (1, 3) ?

1. 0.2
2. 0.4
3. 0.6
4. 0.8

Answer 1

Correct Answer - Option 1 : 0.2

The correct answer is option 1.

The function f(1,3) pass the values to m,n. Then the value will typecast to float and result=0.3333. Then it enters into else statement the function f is f(2,9). 

And finally it returns result as 0.20000003.
∴ Hence the correct answer is 0.2.