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If f(x) = sin2 3x , then find the f'(x) at x = 15°.

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 If f(x) = sin2 3x , then find the f'(x) at x = 15°.
1. -3
2. 1
3. 0
4. 3
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Correct Answer - Option 4 : 3

Calculation:

f(x) = sin2 3x

On differentiating, we get

f'(x) = 6 sin 3x cos 3x

Now put x= 15°  we get 

f'(x) = 6 sin 45°  cos 45° 

= 3

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