Question

A thermal power plant generates the power of 1000 MW. 900 × 10⁷ kJ/h of energy. The rate at which heat is rejected from the this power plant will be:

1. 500 MW
2.

1000 MW

3. 250 MW
4. 1500 MW

Answer 1

Correct Answer - Option 4 : 1500 MW

Concept:

Energy released by the coal = 900 × 107 kJ/hr = 2500 × 106 J/s = 2500 MW

Work output = 1000 MW

Heat rejected from the power plant will be

QR = QS - W = 2500 – 1000 = 1500 MW