Correct Answer - Option 3 : 33 kmph
Concept:
Speed = Distance/Time
Relative speed = speed of train 1 + speed of train 2 ; when both moving in opposite direction
Calculation:
⇒ Let the speed of the second train be S kmph
240m = 0.24 km
260m = 0.26 km
⇒ (0.24 + 0.26)/(17 + S) = 36/(60 × 60)
⇒ 0.5 × 100 = (17 + S)
⇒ S = 33 kmph
∴ The required speed of the second train will be 33 kmph.