Correct Answer - Option 1 : 0.125
Concept:
As we know that the relationship between modulus of elasticity E, shear modulus G, bulk modulus K and Poisson’s ratio μ
E = 3K(1-2μ)
E = 2G(1+μ)
\(E = \frac{{9KG}}{{3K + G}}\)
\(μ = \frac{{3K - 2G}}{{6K + 2G}}\)
Calculation:
Given:
K= G
\(μ = \frac{{3K - 2G}}{{6K + 2G}}\)
\(μ = \frac{{3 - 2}}{{6+ 2}}\)
\(μ = \frac{{1}}{{8}}\)
μ = 0.125