Correct Answer - Option 3 : 3/32
Calculation:
For any n ≥ 1, an = 3 (an+1 + an+1 + ........)
∴ a1 = 3 (a2 + a3 + -----) or r = 1⁄4 and
a1 + a2 + ---- = (4 × a1)/3 = 32 (as given)
∴ a1 = 24
The GP is 24, 6, 1.5, 1.5/4, 1.5/16
⇒ a5 = 3/32
For an infinite GP if the common-ratio is less than 1 the sum of series = a/(1 - r)