Correct Answer - Option 4 : 11.3 minutes
Concept:
Solidification time
\({t_s} = K \times {\left( {\frac{V}{{SA}}} \right)^2}\)
where, V = volume of casting, SA = surface area of casting, K = solidification factor
- Volume represents the amount of heat content
- The surface area represents the amount of heat transfer
Calculation:
Given:
Casting 1
Length = 200 mm, Breadth = 200 mm, Height = 70 mm
Solidification time (ts) for casting 1 = 10 min
\(20 = K \times {\left( {\frac{{100 \times 100 \times 100}}{{2 \times \left( {10000 + 10000 + 10000} \right)}}} \right)^2} \Rightarrow K = 0.072\)
Casting 2
Length = 100 mm, Breadth = 100 mm, Height = 50 mm
Solidification time (ts) for casting 2
\({t_s} = 0.072\; \times {\left( {\frac{{100 \times 100 \times 50}}{{2 \times \left( {10000 + 5000 + 5000} \right)}}} \right)^2} = 11.25\;min\)