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Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A is

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Calculation:

Let speed of car 1 be a kmph.

Speed of car 2 = a/2 kmph

Time taken by car 1 be b minutes

Time taken by car 2 = (b + 60) minutes

⇒ b = Distance/a

⇒ (b + 60) = 3Distance/(a/2)

⇒ 6b = b + 60

⇒ b = 12

∴ Time taken by car 1 in reaching P is 12 minutes

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