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Consider the sliding window flow-control protocol operating between a sender and a receiver over a full-duplex error-free link. Assume the following:

1. The time taken for processing the data frame by the receiver is negligible.

2. The time taken for processing the acknowledgement frame by the sender is negligible.

3. The sender has infinite number of frames available for transmission.

4. The size of the data frame is 2,000 bits and the size of the acknowledgment frame is 10 bits.

5. The link data rate in each direction is 1 Mbps (= 106 bits per second).

6. One way propagation delay of the link is 100 milliseconds.

The minimum value of the sender's window size in terms of the number of frames, (rounded to the nearest integer) needed to achieve a link utilization of 50% is ______

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Answer: 50 to 52

Formula:

Efficiency (η ) = \(\frac{{Useful\;Time}}{{Total\;time}}\)

Explanation:

Propagation Delay = 100 ms

Transmission delay of the packet = \(\frac{{2000}}{{1000000}}\) = 0.002 = 2 ms

Transmission delay of the ack frame = \(\frac{{10}}{{1000000}}\) = 0.00001 = 0.01 ms

∴ 0.5 = \(\frac{w\times 2}{{2 + 100+ 0.01 + 100}}\)       //w=sender window size

0.5 = \(\frac{w\times 2}{202.01}\) 

w = 50.5

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