Question

In how many ways can you arrange 5 green balls ,4 red balls, 3 blue balls and 2 white ball in a line If balls of the same color are indistinguishable?

Answer 1

Number of ways = \(\frac{14|!}{5!4!3!2!}= \frac{14\times13\times12\times11\times10\times9\times8\times7\times6\times5!}{5!\times24\times6\times2}\) 

= 14 x 13 x 11 x 10 x 9 x 2 x 7

 = 2522520