Correct Answer - Option 1 : 120 cm
2
Given:
Sides of cyclic Quadrilateral 20, 16, 9 and 5 cm
Concept used:
Quadrilaterals
Calculation:
Let the semi perimeter of cyclic Quadrilateral be P
P = \(\frac{{20 \ +\ 16 \ +\ 9 \ +\ 5}}{2}\)
P = 25
Area of Cyclic Quadrilateral = \(\sqrt {\left( {p - a} \right)\left( {p - b} \right)\left( {p - c} \right)\left( {p - d} \right)} \)
Area = \(\sqrt {\left( {25 - 20} \right)\left( {25 - 16} \right)\left( {25 - 9} \right)\left( {25 - 5} \right)} \)
Area = \(\sqrt {5 \times 9 \times 16 \times 20} \)
Area = 120 cm2