Correct Answer - Option 1 : No two expressions represent same set
Given:
X = P ∩ Q ∩ R
Y = (P ∩ Q) ∪ (P ∩ R) ∪ (Q ∩ RC)
Z = (Q ∪ PC) ∩ (P ∪ R) ∪ (P ∪ Q) ∩ P ∩ (PC ∪ R)
Formula used:
Property-1: A ∪ B = B ∪ A
Property-2: A ∩ B = B ∩ A
Property-3: A ∩ Ac = ϕ
Property-4: A ∪ Ac = ∪
Property-5: (A ∪ B) ∩ (B ∪ C) = A ∪ (B ∩ C)
Property-6: (A ∩ B) ∪ (B ∩ C) = A ∩ (B ∪ C)
Property-7: A ∪ ϕ = ϕ ∪ A = A
Property-8: A ∩ ϕ = ϕ ∩ A = A
Calculation:
X = P ∩ Q ∩ R ........(1)
Y = (P ∩ Q) ∪ (P ∩ R) ∪ (Q ∩ RC)
using property- 6
Y = P ∩ (Q ∪ R) ∪ (Q ∩ RC) ......(2)
Z = (Q ∪ PC) ∩ (P ∪ R) ∪ (P ∪ Q) ∩ P ∩ (PC ∪ R)
⇒ Z = (Q ∪ PC) ∩ (P ∪ R) ∪ (P ∪ Q) ∩ (P ∩ PC) ∪ ( P ∩ R) (using P-6)
⇒ Z = (Q ∪ PC) ∩ (P ∪ R) ∪ (P ∪ Q) ∩ ϕ ∪ ( P ∩ R) (using P-3)
⇒ Z = (Q ∪ PC) ∩ (P ∪ Q) ∪ (P ∪ R) ∩ ( P ∩ R) (using P-1, P-7)
⇒ Z = Q ∪ (Pc ∩ p) ∪ (P ∪ R) ∩ ( P ∩ R) (using P-5)
⇒ Z = Q ∪ ϕ ∪ (P ∪ R) ∩ ( P ∩ R) (using P-3)
⇒ Z = Q ∪ (P ∪ R) ∩ ( P ∩ R) ......(3)
Hence, from equation (1), (2) and (3), we can conclude that no two expressions represent same set.