Calculation:

We get on prime factorizing

⇒ 2^{4} × 3^{5} × 2^{4} × 5^{4}

⇒ 2^{8} × 3^{5} × 5^{4}

We get the perfect squares factors which is greater than 1, when the power of factor is even.

For the prime number 2,

We get 2^{0}, 2^{2}, 2^{4}, 2^{6}, 2^{8} there are 5 cases

For the prime number 3,

We get 30, 32, 34 there are 3 cases

For the prime number 5,

We get 50, 52, 54 there are 3 cases

The total number of factors having even power = 5 × 3 × 3 = 45

But, there is 1 case, we get 20 × 30 × 50 = 1

The factor is equal to 1, so we need to eliminate it because we need a factor greater than 1

The total number of factors having even power which is greater than 1 = 45 - 1 = 44

**∴ The total number of factors having even power which is greater than 1 is 44.**