Correct Answer - Option 3 : 18
Calculation:
Men × day = total work
A and B together finish a task in 12 days.
A had worked half as efficiently as she usually does, and B had worked thrice as efficiently as he usually does, the task would have been completed in 9 days.
According to the question,
⇒ (A + B)× 12 = (A/2 + 3B)× 9
⇒ 12A + 12B = (9/2)A + 27B
⇒ (12 – 9/2)A = (27 – 12)B
⇒ 15A = 30B
⇒ A/B = 2/1
A efficiency is 2 unit work in a day, B efficiency is 1 unit work in a day
⇒ total work = (A + B)× 12
⇒ (2 + 1)× 12
⇒ 36 unit
A take to finish the task if she works alone at her usual efficiency
⇒ 36/2
⇒ 18 days
∴ A take to finish the task if she works alone at her usual efficiency would be 18 days.