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While measuring linear distance with a tape by applying normal tension, which of the following corrections is automatically rectified?
1. Correction due to sag only
2. Correction due to pull only
3. Correction due to sag and pull
4. Correction due to alignment

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Correct Answer - Option 3 : Correction due to sag and pull

Explanation

The pull or tension which when applied to a tape suspended in the air, equalizes the correction due to pull and sag is known as Normal tension.

Correction due to pull is given by :

\({{\rm{C}}_{\rm{p}}} = \frac{{\left( {{\rm{P}} - {{\rm{P}}_{\rm{o}}}} \right){\rm{L}}}}{{{\rm{AE}}}}\)

Where,

P = Pull applied,

Po = Pull applied at the time of standardization of tape,

L = Length of tape measured,

A = cross-sectional area of tape, and

E = Modulus of elasticity of tape material

Correction due to sag is given by:

\({{\rm{C}}_{\rm{s}}} = \frac{{{{\rm{W}}^2}{\rm{L}}}}{{24{{\rm{P}}^2}}}\)

Equating both the corrections of pull and sag, the value of pull P can be calculated:

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