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A wire of resistance RΩ is cut into ten equal parts which are then joined in parallel. The new resistance is:
1. 100R Ω
2. 10R Ω
3. R/100 Ω
4. R/10 Ω

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Correct Answer - Option 3 : R/100 Ω

Concept: The property by which an electric conductor opposes the flow of current through it is called as the resistance of the conductor.

  • It is denoted by R.
  • The SI unit of resistance is Ohm (Ω).

\({\bf{Resistance}}\left( {\bf{R}} \right){\rm{}} = \frac{{\rho l}}{A}\)

Where ρ is the resistivity of the conductor, l is the length of the conductor and A is the cross-sectional area.

Explanation:

  • When we stretch the wire then length increases but cross-sectional are decreases.
  • But the total volume of the wire will remain constant.
  • So we will write the formula of resistance in terms of volume (V).

Volume (V) = area (A) × length (l)

So A = V/l

\({\bf{Resistance}}\left( {\bf{R}} \right){\rm{}} = \frac{{\rho l}}{A}\)

Given that,

The resistance of a wire is proportional to its length R α L

The wire is cut into 10 equal parts. So, the resistance of each part = R/10

Then all  10 wires are connected in parallel. Then the equivalent resistance is

\(\frac{1}{R_{eq}}=\frac{1}{\frac{R}{10}}+\frac{1}{\frac{R}{10}}+.......\left ( 10\;times \right )\)

\(\frac{1}{R_{eq}}=\frac{100}{R}\)

 The new resistance is \(R_{eq}=\frac{R}{100}\)

  • Resistance can also be written as

\({\rm{Resistance}}\left( {\rm{R}} \right) = \frac{{\rho l}}{A} = \frac{{\rho l}}{{V/l}} = \frac{{\rho {l^2}}}{V}\)

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