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The path difference between the two wavefronts emitted by two coherent sources of wavelength 6280 A° is 2.5 micron. The phase difference between the wavefronts in radian is:
1. 25 
2. 2.5π 
3. 20
4. 25π

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Best answer
Correct Answer - Option 1 : 25 

The correct answer is option 1) i.e. 25

CONCEPT:

  • Coherent sources: Two sources are coherent if the waves from these sources have the same frequency and same phase difference.
    • For a given wave, its wavelength (λ), frequency (f), and speed of light in a vacuum (c) are related as follows:

\(λ =\frac{c}{f}\)

  • Phase difference is the difference in the phase angle between two waves.
  • Path difference is the difference in the path traversed by the two waves. 
  • The phase difference (Δϕ) and path difference (Δx) for any two waves of the same frequency is given by:

\(\Rightarrow Δ x=\frac{λ } {2\pi }× Δ ϕ\)

Where λ is the wavelength of the waves.

CALCULATION:

Given that:

Wavelength of the waves, λ = 6280 A° = 6280 × 10-10 m

Path difference, Δx = 2.5 micron = 2.5 × 10-6 m

We know, 

\(\Rightarrow λ =\frac{c}{f} \Rightarrow \lambda \propto \frac{1}{f}\) (∵ speed of light is a constant value)

  • Therefore, if two given waves have the same wavelength and phase difference, they will have the same frequency and can be considered as coherent sources.

Using the relation, 

\(\Rightarrow Δ x=\frac{λ } {2\pi }× Δ ϕ\)

\(\Rightarrow 2.5 \times 10^{-6} =\frac{6280 × 10^{-10}} {2\pi } \times \Delta\phi\)

\(\Rightarrow \Delta\phi = \frac{2.5 \times 10^{-6} \times 2\pi }{6280 × 10^{-10}} = 25\: radian\)

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