Correct Answer  Option 1 : 0.1 m
CONCEPT:

Concave mirror: If the inner surface of the spherical mirror is the reflecting surface, then it is called a concave mirror. It is also called a focusing mirror/converging mirror.
 The size of the image produced by these mirrors can be larger or smaller than the object, depending upon the distance of the object from the mirror.
 The concave mirror can form both real and virtual images of any object.

Mirror formula: The expression which shows the relation between object distance (u), image distance (v), and focal length (f) is called the mirror formula.
\(\frac{1}{v} + \frac{1}{u} = \frac{1}{f}\)
Linear magnification (m):
 It is defined as the ratio of the height of the image (hi) to the height of the object (ho).
\(m = \frac{{{h_i}}}{{{h_o}}}\)
 The ratio of image distance to the object distance is called linear magnification.
\(m = \frac{{image\;distance\;\left( v \right)}}{{object\;distance\;\left( u \right)}} =  \frac{v}{u}\)
 A positive value of magnification means virtual an erect image.
 A negative value of magnification means a real and inverted image.
CALCULATION:
Given  f = 0.8 m, m = 4, let U = x
 The magnification of the image is given by
\(\Rightarrow 4 = \frac{V}{u}\)
\(\Rightarrow V = 4x\)
Substituting the value of V and u in the equation for focal length
\(\Rightarrow \frac{1}{f} = \frac{1}{x} \frac{1}{4x} = \frac{5x}{4x^{2}}\)
\(\Rightarrow f =  \frac{4x^{2}}{5x} = \frac{4x}{5}\)
\(\Rightarrow x = \frac{5\times f}{4} = \frac{5\times 0.8}{4} = 0.1 m\)
 Hence, the object must be placed at a distance of 10 cm away from it
 Hence, option 1 is the answer.