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If the average of 3-digit numbers 235, 2a5, a35, 63a and 116 is 333, then what is the product of a – 1, a + 3 and a + 6?


1. 90
2. 240
3. 210
4. 120

1 Answer

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Correct Answer - Option 3 : 210

Given:

Average of 3-digit numbers 235, 2a5, a35, 63a and 116 is 333

Formula used:

Sum of the value of numbers = Average of numbers × number of numbers

Calculation: 

According to question,

Total value of number = 333 × 5

⇒ 235 + 2a5 + a35 + 63a + 116 = 1665

⇒ 2a5 + a35 + 63a = 1314

Now, we have to think of that number in which the unit digit number is 4 because the unit digit of RHS is 5 and the unit digit of LHS is 'a'

So, we have to assume ‘a’ = 4 because in 1314 the last number is 4

Now if we take a = 4, we get 

(2a5 = 245), (a35 = 435), (63a = 634)

⇒ (245 + 435 + 634) = 1314

Here we can see that, a = 4 satisfies the equation

Now, (a – 1) = 4 – 1 = 3

⇒ (a + 3) = 4 + 3 = 7

⇒ (a + 6) = 4 + 6 = 10

∴ The product of 3, 7, 10 is 210.

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