Correct Answer - Option 1 : 127.33 MPa
Concept:
\({\rm{Tensile\;stress}} = \frac{{tensile\;loaad}}{{cross - sectional\;area}}\)
Calculation:
Given Load = 40 kN = 40 × 103 N;
Area = 100 × π mm2
\({\rm{Tensile\;stress}} = \frac{{40\; × \;{{10}^3}}}{{100\pi}} = 127.33\;MPa\)