LIVE Course for free

Rated by 1 million+ students
Get app now
JEE MAIN 2023
JEE MAIN 2023 TEST SERIES
NEET 2023 TEST SERIES
NEET 2023
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
21 views
in Physics by (41.6k points)
closed by
A piece of metal of mass 1 Kg is completely immersed in water. The water level rises by 100 ml. Calculate apparent loss of weight in the metal. (given density of water = 1000 g/cc and g = 9.8 m/s2)
1. 0.00098 N
2. 1 N
3. 9.8 N
4. 0.098 N

1 Answer

0 votes
by (30.0k points)
selected by
 
Best answer
Correct Answer - Option 1 : 0.00098 N

CONCEPT:

  • Archimedes' principle states that when a body immersed in a fluid, whether fully or partially submerged, the upward buoyant force that is exerted on it, is equal to the weight of the fluid that the body displaces.
  • Buoyant force: When an object is submerged in fluid fully or partially, an upward force is exerted on the body. This force is known as the buoyant force. 

Fbuoyant = ρVf g 

where ρf is the density of the fluid in which the object is submerged, Vf is the volume of the displaced fluid (or volume of the object that is submerged inside the fluid)  and g is the gravitational acceleration.

  • The apparent loss of weight in an object, when submerged, is equal to the buoyant force.

CALCULATION:

Given that the Density of water ρw = 1000 g/cc = 1 kg/m3 and g = 9.8 m/s2 

The volume displaced V= 100 ml = 10-4 m3

We know that Apparent loss of weight = Buoyant force

The apparent loss of weight of metal = W = density of fluid × Volume of water displaced × g

W = ρwVw g 

W = 1 kg/m3 × 10-4 m× 9.8 m/s2 

W = 0.00098 N

So the correct answer is option 1. 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...