Correct Answer - Option 1 : Both A and R are individually true and R is the correct explanation of A
Concept:
Causal – degree (order) of denominator ≥ degree of the numerator
Non-causal – degree of denominator < degree of the numerator
Analysis:
H(z) \( = \frac{{{z^3} - 2{z^2} + z \to numerator}}{{{z^2} + \frac{1}{4}z + \frac{1}{8} \to denominator}}\)
Degree of denominator = 2
Degree of numerator = 3
Since the degree of Dr < degree of Nr. Hence, It is a non-causal system.
Eg.
\(H\left( z \right) = \frac{{{z^3} + 4{z^2} + 5z + 9}}{{{z^2} + 4z + 5}} = z + k + \ldots {z^{ - 1}} + \ldots {z^{ - 2}}\)
When the degree of Nr > degree of Dr then the positive power of z comes that’s why the system will be non-causal.
\(H\left( z \right) = \frac{{z + 1}}{{{z^2} + 2z + 1}} = {z^{ - 1}} + {z^{ - 2}} \ldots \)r
In this case degree of Dr > degree of Nr then only negative power of z appears that’s why the system will be causal.