Correct Answer - Option 4 : 100
Concept:
Assume the system is interference limited. i.e,
\(\frac{{{E_b}}}{{{N_0} + {I_0}}} \approx \frac{{{E_b}}}{{{I_0}}}\).
The number of users per cell is:
M ≈ Gp(dB) – Eb/I0(dB)
\(\frac{{{E_b}}}{{{I_O}}} = \frac{{{G_p}}}{{M - 1}}\)
Processing gain is defined as:
\({G_p} = \frac{{{R_{ch}}}}{R}\)
Rch: Chip rate
R: Data rate
Calculation:
The given chip rate is 1 Mbps and the data rate is 1 Kbps.
Processing gain will be 1000.
A maximum number of users is:
M – 1 = 100
M ≈ 100