Correct Answer - Option 3 : 55 Km/hr
Given:
The ratio of the speed of onward journey to the speed of return journey = 5 ∶ 6
Total distance in whole journey = 800 km
Total time taken in whole journey = 16 hours
Concept used:
Average speed = (2 × S1 × S2)/(S1 + S2)
Average speed = (Total distance)/(Total time)
Where,
S1 → First speed
S2 → Second speed
Calculations:
Let the speed of onward and return journey be 5x and 6x respectively.
So, the average speed of train in entire journey = (2 × 5x × 6x)/(5x + 6x) = 60x2/11
Average speed = 800/16
Now,
⇒ 60x2 /11 = 50
⇒ x = 55/6
⇒ Speed of return journey is = 6 × 55/6 = 55 Km/hr