Correct Answer - Option 3 : 3NF
1 NF
A relation R is in first normal form (1NF) if and only if all underlying domains contain atomic values only.
2 NF
A relation R is in second normal form (2NF) if and only if it is in 1NF and every non-key attribute is fully dependent on the primary key.
Example: A → B, B → C , A → C here A is key and relation is in 2NF but A → B, B → C , A → C is transitive
3 NF
A relation R is in third normal form (3NF) if and only if it is in 2NF and every non-key attribute is non-transitively dependent on the primary key. Hence Option 3 is the correct answer.
BCNF
A relation R is in Boyce-Codd normal form (BCNF) if and only if every determinant is a candidate key.