Correct Answer - Option 1 : 0.781
Concept:
we use the following equation to find out the applied shear stress;
τ = C + σ tanϕ
Where, τ = Shear stress; σ = normal stress
C = cohession of soil; ϕ = angle of internal friction or failure plane;
Calculation:
Given:
ϕ = 38∘
As the given soil is cohessionless, hence C = 0
Now, let's put the values into the equation.
∴ τ = 0 + σ × tan 38∘
⇒ τ/σ = tan 38∘
∴ τ/σ = 0.781