Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
352 views
in General by (95.6k points)
closed by
Ultimate bearing capacity (in kN/sq.m) of a square footing on surface of a saturated clay having unconfined compressive strength of 60 kN/sq.m, using Skempton equation will be
1. 150
2. 120  
3. 100
4. 125
5. 180

1 Answer

0 votes
by (98.5k points)
selected by
 
Best answer
Correct Answer - Option 5 : 180

Concepts:

The net ultimate bearing capacity of pure clay soils as per Skempton’s Method is given as:

Qnu = C × Nc

Where, C = cohesion

Nc = Skempton’s bearing capacity factor which depends on Df/B ratio and type of footing. It is given as

Case 1: If footing is on ground surface i.e. Df/B = 0.

For strip footing, Nc = 5

For Square or Circular or rectangular footing, Nc = 6.

Case 2: If Df/B ≥  2.5.

For strip footing, Nc = 7.5

For Square or Circular or rectangular footing, Nc = 9.

Case 3: If 0 < Df/B < 2.5

For strip footing, Nc = 5(1 + 0.2 × Df/B)

For Square or circular footing, Nc = 6(1 + 0.2 × Df/B)

For rectangular footing, Nc = 5(1 + 0.2 × Df/B) × (1 + 0.2×B/L)

Further, the relation between unconfined compressive strength (UCS) and Cohesion (C) of pure clay is given as:

 UCS = 2 × C

Calculation:

UCS = 60 kN/m2 ⇒ C = 60/2   30 kN/m2

In our case footing is square and it is on ground surface i.e. Df/B = 0

Therefore, Nc = 6.

Qnu = C × Nc = 30 × 6 = 180 kN/m2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...