Correct Answer - Option 4 : Successive approximation type

The conversion time of successive approximation type ADC is n T_{clk}.

Where n is the number of bits and T_{clk} is the clock period.

1 T_{clk} is used for the start of the conversion signal and 1 T_{clk} is used for the end of the conversion signal.

Here n = 12

So total conversion time

\(\begin{array}{*{20}{c}}
{ = 12 \times 1\;\mu sec + \;}\\
{}
\end{array}\begin{array}{*{20}{c}}
{1\mu \sec + \;}\\
{\left( {EOC} \right)}
\end{array}\begin{array}{*{20}{c}}
{1\;\mu sec}\\
{\left( {SOC} \right)}
\end{array}\)

= 14 μsec