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∠BAC = 90°, AD is its bisector. IF DE ⟂AC, prove that DE × (AB + AB) = AB × AC.

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∠BAC = 90°, AD is its bisector. IF DE ⟂AC, prove that DE × (AB + AB) = AB × AC.

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It is given that AD is the bisector of ∠A of ΔABC.

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