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In a ΔABC, AB = BC = CA = 2a and AD⟂ BC. Prove that (i) AD =a√3 (ii) area (ΔABC) = √3a^2

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In a ΔABC, AB = BC = CA = 2a and AD⟂ BC. Prove that

(i) AD =a√3 (ii) area (ΔABC) = √3a2

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Best answer

(i) Here, AD⟂ BC.

Clearly, ΔABC is an equilateral triangle.

Thus, in ΔABD and ΔACD

AD = AD   [Common]

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