Correct Answer - Option 4 :
0.016 bar
Concept:
The specific humidity is given by
\(\omega = \frac{{0.622{P_v}}}{{P - {P_v}}}\)
Where ω is specific humidity, P is pressure of air, Pv is partial pressure of vapour
Calculation:
Given P = 1.013 bar, ω = 0.0095 kg/kg of dry air;
From specific humidity formula,
\(0.0095 = \frac{{0.622{P_v}}}{{1.013 - {P_v}}} \Rightarrow {P_v} = 0.01524\;bar\)
Nearest option is 0.016 bar