Correct Answer - Option 2 : 40 dB
Concept:
The gain margin is always calculated at the phase Crossover frequency (ωpc)
The phase Crossover frequency (ωpc) is calculated as:
\(\angle G\left( {j\omega } \right)H\left( {j\omega } \right){\left. \right|_{\omega = {\omega _{pc}}}} = \pm 180^\circ \)
Gain margin \( = \frac{1}{{{{\left| {G\left( {j\omega } \right)H\left( {j\omega } \right)} \right|}_{\omega = {\omega _{pc}}}}}}\)
Calculation:
Given:
\(G(s)=\frac{10}{(s+5)^3}\)
∠G(jω)H(jω) = -180°
\(-3\times tan^{-1}({\frac{ω_{pc} }{5}})= - 180^\circ \)
\(ω_{pc}=5\sqrt{3}\) rad/sec
\(\left| {G\left( {j{ω _{pc}}} \right)H\left( {j{ω _{pc}}} \right)} \right| = 0.01\)
\(G.M.\; = 20\log \frac{1}{a} = 20\log \frac{1}{{0.01}} = 40\;dB\)