Correct Answer - Option 1 : |cos Ω|
Concept:
The Discrete-Time Fourier transform of a signal of infinite duration x[n] is given by
\(X\left( ω \right) = DTFT\left\{ {x\left[ n \right]} \right\} = \mathop \sum \limits_{n = - \infty }^\infty x\left[ n \right]{e^{ - jω n}}\)
Analysis:
\(h(n)=\frac{1}{2}(δ[n]+δ[n-2])\)
H(ejω) = 0.5 + 0.5 e-j2ω
= e-jω [0.5 ejω + 0.5 e-jω]
= e-jω cosω
The magnitude of the frequency response is: |cos ω|