Correct Answer - Option 1 : C(t) = 5e
-2t – e
-t -1
Concept:
The response of a system is nothing but the convolution of the input signal with the impulse response.
For a discrete-time system, the response for an input sequence x(n) will be:
y[n] = x[n] ⊕ h[n]
\(y\left( n \right) = \mathop \sum \limits_{k = - \infty }^{k = \infty } x\left[ k \right]h\left[ {n - k} \right]\)
For a continuous-time signal, the response is given by:
\(y\left( t \right) = \mathop \smallint \limits_{ - \infty }^{ + \infty } x\left( \tau \right)h\left( {t - \tau } \right)d\tau\)
For the continuous-time system, the step response will be:
\(s\left( t \right) = \mathop \smallint \nolimits_{ - \infty }^\infty h\left( t \right)dt\)
where h(t) is the impulse response.
Analysis:
\(H(s)=\frac{(3s^2-2)}{(s^2+3s+2)} \)
X(s) = 1/s
Y(s) = \(\frac{3s^2-2}{s^2+3s+2} \times \frac{1}{s}\)
Y(s) = \(\frac{A}{s}+\frac{B}{s+1}+\frac{C}{s+2}\)
A = -1
B = -1
C = 5
y(t) = -1 - e-t + 5 e-2t