Correct Answer - Option 2 : 89.4%
Concept:
The total transmitted power for an AM system is given by:
\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)
Pc = Carrier Power
μ = Modulation Index
The above expression can be expanded to get:
\({P_t} = {P_c} + P_c\frac{{{μ^2}}}{2}\)
The total power is the sum of the carrier power and the sideband power, i.e.
\({P_s} = P_c\frac{{{μ^2}}}{2}\)
Calculation:
Given: Pc = 1000 W and Ps = 200W
\({P_s} = P_c\frac{{{μ^2}}}{2}\)
\(μ^2=\frac{800}{1000}\)
μ = 0.8944
% Modulation = 89.44%