Correct Answer - Option 2 : 8.43 kVAR
Concept:
Rating of the capacitor:
Leading kVAR supplied by p.f. correction equipment
Q = P (tan φ1 − tan φ2)
P = Active power in kW
ϕ1 = angle before power factor correction
ϕ2 = angle after power factor correction
Calculation:
Given that P = 20 kW, cos ϕ1 = 0.8, cos ϕ2 = 0.95
Now Rating of the capacitor
Q = P (tan φ1 − tan φ2)
Q = 20 × {tan(cos-10.8) − tan(cos-10.95)}
Q = 20 × 0.4261 = 8.43 kVAR