3B → P
rate of reaction = \(-\frac13\frac{\Delta[B]}{\delta t}=\frac{\Delta[P]}{\Delta t}\)
\(=-\frac13\times\frac{(0.3-0.6)}{20\times60}\)
\(=\frac13\times\frac{0.3}{1200}\)
= 8.33 x 10-5 mol L-1 S-1
Hence, the qve. rate of reaction between 20 min will be
8.33 x 10-5 Mol L-1 S-1