Correct Answer - Option 2 : 19/12

**Given:**

d = 4a/3

S_{17} = 595/12

**Formula used:**

S_{n} = n/2 × [2a + (n – 1) d]

Where, a = first term, n = number of terms and d = common difference

**Calculation:**

S_{17} = 17/2 × [2a + (17 – 1) d]

⇒ 595/12 = 17/2 × [2a + 16 × (4a/3)]

⇒ 35/6 = 2a + 64a/3

⇒ 35/6 = 70a/3

⇒ a = 1/4

∴ d = 4a/3 = 1/3

So, T_{5} = a + (n – 1) d

⇒ T_{5} = ¼ + (5 – 1) × (1/3)

⇒ T_{5} = ¼ + 4/3

∴ T_{5} = 19/12