Correct Answer - Option 2 : 19/12
Given:
d = 4a/3
S17 = 595/12
Formula used:
Sn = n/2 × [2a + (n – 1) d]
Where, a = first term, n = number of terms and d = common difference
Calculation:
S17 = 17/2 × [2a + (17 – 1) d]
⇒ 595/12 = 17/2 × [2a + 16 × (4a/3)]
⇒ 35/6 = 2a + 64a/3
⇒ 35/6 = 70a/3
⇒ a = 1/4
∴ d = 4a/3 = 1/3
So, T5 = a + (n – 1) d
⇒ T5 = ¼ + (5 – 1) × (1/3)
⇒ T5 = ¼ + 4/3
∴ T5 = 19/12