Question

A shopkeeper purchases a packet of 90 pencils at ₹ 5 per pencil. He sells a part of the packet at a profit of 20% and on the remaining part, he incurs a lot of 20%. If his overall profit on the whole packet is 20/9%. Then, the number of pencils, he sold at profit is –
1. 40
2. 30
3. 60
4. 50
5. None of these

Answer 1

Correct Answer - Option 4 : 50

20/9% = 1/45

Total number of pencils = 90 at ₹ 5 per pencils

Suppose the number of pencils sold at 20% profit = x

So, the number of pencils sold at 20% loss = (90 – x)

According to condition –

⇒ 5 × [x × 120/100 + (90 – x) × 80/100] = 5 × (90 × 46/45)

⇒ 6x/5 + (90 – x) × 4/5 = 92

⇒ 6x/5 + 72 – 4x/5 = 92

⇒ 2x/5 = 92 – 72

⇒ 2x/5 = 20

⇒ x = (20 × 5)/2

⇒ x = 50

∴ The number of pencils sold at profit is 50.